Regview: the 2 minutes crack
(encrypted counters)

by Rundus

(20 September 1997)

Courtesy of Fravia's page of reverse engineering

Well, we had some serious emailing problems with this essay from Rundus, which has been written, as you can see, two weeks ago. Please send always as CUT AND PASTED text, and if possible use Ultraedit32 to compose your poems. This essay is interesting and it deals with a pretty important register sniffer. Very good reasons to read and head it. 
THE TWO MINUTE CRACK
03 September 1997, by Rundus
The program is Regview version 2.2, get it at ftp.winsite.com or ftp.orst.edu The program has a few more tools than Regedit.exe. For example, you can compare directories,Registry, etc. It has a Nag message and a 30 days trial. To begin with I always run a program Easyclean32 v1.04 ( great program GET IT http://www.idv.de./homepages/bernd, my crack name:DONE s/n:$DC94412Dk ) to detect any changes make to my hard disk,when installing any new programs. The first thing I look at is the register and sure enough the Regview program had added the key HKEY_LOCAL_MACHINE\SOFTWARE\classes\VR_T, that contained a encrypted counter value CLID 0xffffff08 (-248) So what did I do, I changed it to 0xffffff07 and goodbye Nag window and 30 days limited. BUT OUT OF INTEREST,I LOADED IT INTO WDASM AND FOUND THIS. :004629BD 812D9016470007FFFFFF sub dword ptr [00471690], FFFFFF07 :004629C7 833D9016470000 cmp dword ptr [00471690], 00000000 :004629CE 750C jne 004629DC ;CHANGE TO JE 740c :004629D0 C6058C16470001 mov byte ptr [0047168C], 01 :004629D7 E960010000 jmp 00462B3C ;with that changed the counter is not incremented and no regview Nag message appears. Also when you enter in a Reg No the encrypted counter value is set to ffffff07 unbelievable :) * Referenced by a Jump at Address:004629CE(C) :004629DC 833D901647001E cmp dword ptr [00471690], 0000001E :004629E3 7F0D jg 004629F2 :004629E5 833D9016470000 cmp dword ptr [00471690], 00000000 :004629EC 0F8DE1000000 jnl 00462AD3 * Referenced by a Jump at Address:004629E3(C) | :004629F2 8D55F4 lea edx, dword ptr [ebp-0C] :004629F5 B801000000 mov eax, 00000001 :004629FA E84DFFF9FF call 0040294C :004629FF 8B45F4 mov eax, dword ptr [ebp-0C] * Possible StringData Ref from Code Obj ->"try" | :00462A02 BAAC2B4600 mov edx, 00462BAC :00462A07 E8A40DFAFF call 004037B0 :00462A0C 7529 jne 00462A37 :00462A0E B908FFFFFF mov ecx, FFFFFF08 * Possible StringData Ref from Code Obj ->"CLSID" | :00462A13 BA9C2B4600 mov edx, 00462B9C :00462A18 8B45FC mov eax, dword ptr [ebp-04] :00462A1B E85811FDFF call 00433B78 :00462A20 B201 mov dl, 01 :00462A22 8B8368030000 mov eax, dword ptr [ebx+0368] :00462A28 E8D7EBFAFF call 00411604 :00462A2D E8B608FAFF call 004032E8 :00462A32 E922010000 jmp 00462B59 * Referenced by a Jump at Address:00462A0C(C) | :00462A37 6A00 push 00000000 :00462A39 668B0DB02B4600 mov cx, word ptr [00462BB0] :00462A40 B202 mov dl, 02 * StringData Ref from Code Obj ->"Maximum number of trials has been " ->"reached! To continue use of this " ->"program, you need to register" ->"now!" | :00462A42 B8BC2B4600 mov eax, 00462BBC :00462A47 E87C03FDFF call 00432DC8 :00462A4C 48 dec eax :00462A4D 757B jne 00462ACA :00462A4F 8D45F8 lea eax, dword ptr [ebp-08] :00462A52 50 push eax :00462A53 33C9 xor ecx, ecx AND ALSO THIS TO PRODUCE THE REAL REG No, WITH HELP FROM SOFTICE V3 * Possible StringData Ref from Code Obj ->"Enter the register key:" | :0046E3E7 BABCE44600 mov edx, 0046E4BC * Possible StringData Ref from Code Obj ->"Enter register key" | :0046E3EC B8DCE44600 mov eax, 0046E4DC :0046E3F1 E86A4DFCFF call 00433160 :0046E3F6 8D4DF4 lea ecx, dword ptr [ebp-0C] :0046E3F9 8B55F8 mov edx, dword ptr [ebp-08] abcdefghijkl is XOR with the numbers you have entered in. e.g 1313131313 serial No entered in 1 = 31h 3 = 33h a = 61h b = 62h XOR = 50h XOR = 51h 50h = P 51h = Q So 1313131313 = PQRWTUVVXY This is compared with TQWUPTU]YY[[ the real XOR number. Working backwards T = 54h Q = 51h a = 61h b = 62h XOR = 35h XOR = 33h 35h = 5 33h = 3 So TQWUPTU]YY[[ = 534152250307 the real serial No What does the real serial number do? You have guessed right. It sets the counter to the value of 0xffffff07 * Possible StringData Ref from Code Obj ->"abcdefghijkl" | :0046E3FC B8F8E44600 mov eax, 0046E4F8 :0046E401 E85A33FDFF call 00441760 ;CALL TO CALCULATE REG No :0046E406 8B55F4 mov edx, dword ptr [ebp-0C] :0046E409 8D45F8 lea eax, dword ptr [ebp-08] :0046E40C E8AF51F9FF call 004035C0 :0046E411 8B45F8 mov eax, dword ptr [ebp-08] * Possible StringData Ref from Code Obj ->"TQWUPTU]YY[[" | :0046E414 BA10E54600 mov edx, 0046E510 :0046E419 E89253F9FF call 004037B0 :0046E41E 7537 jne 0046E457 :0046E420 B101 mov cl, 01 * Referenced by a Jump at Address:00441809(C) | :004417CB 8B45FC mov eax, dword ptr [ebp-04] :004417CE 0FB67C18FF movzx edi, byte ptr [eax + ebx - 01] ;MOVE 61h ( a ) INTO EDI :004417D3 8B45F8 mov eax, dword ptr [ebp-08] ;MOVE 31h ( 1 ) INTO EAX :004417D6 0FB64418FF movzx eax, byte ptr [eax + ebx - 01] :004417DB 8945F0 mov dword ptr [ebp-10], eax :004417DE 8D45F8 lea eax, dword ptr [ebp-08] :004417E1 B901000000 mov ecx, 00000001 :004417E6 8BD3 mov edx, ebx :004417E8 E8F720FCFF call 004038E4 :004417ED 8D45EC lea eax, dword ptr [ebp-14] :004417F0 8B55F0 mov edx, dword ptr [ebp-10] :004417F3 33D7 xor edx, edi ;XOR 31h WITH 61h EDX NOW = 50h :004417F5 E8421EFCFF call 0040363C :004417FA 8B45EC mov eax, dword ptr [ebp-14] :004417FD 8D55F8 lea edx, dword ptr [ebp-08] :00441800 8BCB mov ecx, ebx :00441802 E82521FCFF call 0040392C :00441807 43 inc ebx :00441808 4E dec esi :00441809 75C0 jne 004417CB For anyone who does not know what Xoring is. truth table inputs A | B for e.g a = 61h binary 01100001 0 | 0 = 0 1 = 31h binary 00110001 0 | 1 = 1 answer = 01010000 1 | 0 = 1 1 | 1 = 0 01010000 = 50h = P Well that's all for now and I hope someone finds this tutorial useful. cheers Rundus (c) Rundus 1997. 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